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Full disclosure
[0day-rubbish] Royal Server 5.04.50529.0 Local privilege escalation to LocalSystem on the execution path without credential override (7.2)
[0day-rubbish] core-admin 1.0.164 (build 16468) Systemic shell command injection via ineffective quote escaping (8.8)
[0day-rubbish] OP5 Monitor 9.20 Command injection surviving the CVE-2025-34115 patch (OPT-IN fix ineffective) (8.8)
[0day-rubbish] QuantaStor 6.8.3.018 Command injection in the alert-mail command via the smtpPassword field (8.8)
[0day-rubbish] SmarterMail 100.0.9693 (Build 9693) Antivirus command-line configuration executing as NT AUTHORITY\SYSTEM (7.2)
[0day-rubbish] Jitterbit Agent 12.8.1.6 (Docker jitterbit/agent:12.8.1.6) Unauthenticated SOAP with hard-coded credentials leading to OS command execution (9.8)
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[0day-rubbish] DBxtra .NET 13.1.1.0 Unauthenticated SOAP API to xp_cmdshell code execution (9.8)
**Subject:** CVE-2026-2035703: Tozed ZLT X300 5G CPE — Unauthenticated Remote Root Code Execution via TR-069 Command Injection (CVSS 9.8)
CVE-2026-52307: Stored XSS in 1CMS v5.6
HP Easy Start for macOS: CVE-2026-12554 / CVE-2026-12555 /CVE-2026-12556
Next.js 16.4.0-canary.13 Image Optimizer DNS Rebinding TOCTOU SSRF Still Exists
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Flextype v1.0.0-alpha.3 Stored Fetch Shortcode Allows Server-Side Request Forgery
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What it mean...
PostPosted: Wed Jan 14, 2009 11:28 am Reply with quote
indish3ll
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Joined: Jan 10, 2009
Posts: 23




Query: SELECT NULL FROM se_classifieds LEFT JOIN se_users ON se_classifieds.classified_user_id=se_users.user_id LEFT JOIN se_classifiedvalues ON se_classifieds.classified_id=se_classifiedvalues.classifiedvalue_classified_id WHERE CASE WHEN se_classifieds.classified_user_id='0' THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_REGISTERED) AND '0'<>0) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_ANONYMOUS) AND '0'=0) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_FRIEND) AND '0'<>0 AND (SELECT TRUE FROM se_friends WHERE friend_user_id1=se_classifieds.classified_user_id AND friend_user_id2='0' AND friend_status='1' LIMIT 1)) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_SUBNET) AND '0'<>0 AND (SELECT TRUE FROM se_users WHERE user_id=se_classifieds.classified_user_id AND user_subnet_id='0' LIMIT 1)) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_FRIEND2) AND '0'<>0 AND (SELECT TRUE FROM se_friends AS friends_primary LEFT JOIN se_users ON friends_primary.friend_user_id1=se_users.user_id LEFT JOIN se_friends AS friends_secondary ON friends_primary.friend_user_id2=friends_secondary.friend_user_id1 WHERE friends_primary.friend_user_id1=se_classifieds.classified_user_id AND friends_secondary.friend_user_id2='0' AND se_users.user_subnet_id='0' LIMIT 1)) THEN TRUE ELSE FALSE END AND se_classifieds.classified_classifiedcat_id=benjoe:$1$admin123$82WhhzvHQI7y1Taq83tiU1


Running sql injection am getting above error.. can any one help me to get correct syntx

don understand what am missing..

Thanks in advance..
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What it mean...
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