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www.waraxe.us Forum Index -> Newbies corner -> Help with sql injection
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Help with sql injection
PostPosted: Mon Oct 17, 2005 12:27 pm Reply with quote
mcxar
Regular user
Regular user
Joined: Oct 17, 2005
Posts: 5




I have tried all there is,like simple pocs but the database is not spiting any errors,can someone give me a hand since im kinda new to injection,here is the form:

Code:
<form action="?mod=chpass" method="post">
Login: <input type="text" name="userid" /><br />

Old Password: <input type="password" name="pass" /><br />
New Password: <input type="password" name="pass2" /><br />
Confirm New: <input type="password" name="pass3" /><br />
<input type="Submit" value="Change password" />
</form>


This is to change password since is the only form available to exploit,no login form available so i want to get a list of users and md5 passwords if possible.

All i could collect was a raw login in witch you can see the sql structure from another site,supposed to be stored like this:

INSERT INTO `login` (`account_id`, `userid`, `user_pass`, `sex`, `email`) VALUES ('1', 's1', 'p1', 'S','a@a.com');
INSERT INTO `login` (`account_id`, `userid`, `user_pass`, `sex`, `email`) VALUES ('2', 's2', 'p2', 'S','a@a.com');

Thanks in advance.
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PostPosted: Tue Oct 18, 2005 1:07 am Reply with quote
mcxar
Regular user
Regular user
Joined: Oct 17, 2005
Posts: 5




Update,i found the file that precess the form:

Code:
include("includes/config.inc.php");

echo "<form action=\"?page=changepass\" method=\"post\">Login:<br /><input type=\"text\" name=\"userid\" /><br />
Old Password:<br /><input type=\"password\" name=\"pass\" /><br />
New Password:<br /><input type=\"password\" name=\"pass2\" /><br />
<input type=\"Submit\" value=\"Change password\" />
</form>";

function error($string){
echo $string;
}

if (isset($_POST['userid']) != NULL && isset($_POST['pass']) != NULL && isset($_POST['pass2']) != NULL) {
$link = @mysql_connect($mysqlserver,$mysqluser,$mysqlpass);
$userid = mysql_real_escape_string($_POST['userid']);
$pass = mysql_real_escape_string($_POST['pass']);
$pass2 = mysql_real_escape_string($_POST['pass2']);
if (strlen($userid) <= 3){
error("This login is wrong!");
}
elseif (strlen($pass) <= 3 || strlen($pass2) <= 3 || $pass == NULL || $pass2 == NULL){
error("Your password must contain at least 4 symbols.");
} else {
$result = mysql_query("SELECT `user_pass` FROM $server.login WHERE `userid` = '$userid'");
if(mysql_result($result,0) != $pass && mysql_result($result,0) != NULL){
error("Sorry, but password is wrong.");
} else {
$checklogin = "SELECT `userid` FROM $server.login WHERE `userid` = '$userid'";
$checkloginres = mysql_query($checklogin);
if(mysql_result($checkloginres,0) == NULL){
error("Sorry, but your login doesn't exist.");
} else {
$query = "UPDATE $server.login SET `user_pass` = '$pass2' WHERE `userid` = '$userid'";
mysql_query($query);
echo "Your password changed.";
}
}
}
mysql_close($link);
}


Still needing a hand,thanks.
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Help with sql injection
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