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Full disclosure
[0day-rubbish] VMS 6.48.809 Authenticated command injection to root RCE (8.8)
[0day-rubbish] ONE Reporter 13.1 Authenticated RCE / privilege escalation via CommandExecutor (8.8)
[0day-rubbish] Gemini 7.3.0 Authenticated SQL injection to xp_cmdshell RCE (8.8)
[0day-rubbish] RoboTask 11.0.5.1229 Unauthenticated REST API remote task execution (9.8)
[0day-rubbish] ActiveFax Server 10.70 Unauthenticated LPD Ghostscript %pipe% SYSTEM RCE (9.8)
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[0day-rubbish] Datalore On-Premises 2026.2.3 Unauthenticated RCE via InteractiveReport access-mapping flaw (9.8)
APPLE-SA-08-18-2026-1 Safari 26.6.1
Cudy WR3000: Hard-coded JWT Secret to Root Command Injection
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Security advisory: Pre-authentication SYSTEM RCE (Zip-Slip plugin planting) in Output Messenger Server 2.0.x (>= 2.0.63) (Srimax Software (Output Technology))
Security advisory: Pre-authentication RCE (arbitrary file write) in RapidDeploy 5.2.2 (MidVision)
Security advisory: Authenticated RCE (second-order SQL injection) in Lansweeper 12.2.1.0 (web reports 12.2.1.6) (Lansweeper)
Security advisory: Authenticated RCE (command injection) in Kerio Connect 10.0.9 Patch 2 (build 10320) (GFI Software)
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www.waraxe.us Forum Index -> Suggestions -> What it mean...
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What it mean...
PostPosted: Wed Jan 14, 2009 11:28 am Reply with quote
indish3ll
Regular user
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Joined: Jan 10, 2009
Posts: 23




Query: SELECT NULL FROM se_classifieds LEFT JOIN se_users ON se_classifieds.classified_user_id=se_users.user_id LEFT JOIN se_classifiedvalues ON se_classifieds.classified_id=se_classifiedvalues.classifiedvalue_classified_id WHERE CASE WHEN se_classifieds.classified_user_id='0' THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_REGISTERED) AND '0'<>0) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_ANONYMOUS) AND '0'=0) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_FRIEND) AND '0'<>0 AND (SELECT TRUE FROM se_friends WHERE friend_user_id1=se_classifieds.classified_user_id AND friend_user_id2='0' AND friend_status='1' LIMIT 1)) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_SUBNET) AND '0'<>0 AND (SELECT TRUE FROM se_users WHERE user_id=se_classifieds.classified_user_id AND user_subnet_id='0' LIMIT 1)) THEN TRUE WHEN ((se_classifieds.classified_privacy & @SE_PRIVACY_FRIEND2) AND '0'<>0 AND (SELECT TRUE FROM se_friends AS friends_primary LEFT JOIN se_users ON friends_primary.friend_user_id1=se_users.user_id LEFT JOIN se_friends AS friends_secondary ON friends_primary.friend_user_id2=friends_secondary.friend_user_id1 WHERE friends_primary.friend_user_id1=se_classifieds.classified_user_id AND friends_secondary.friend_user_id2='0' AND se_users.user_subnet_id='0' LIMIT 1)) THEN TRUE ELSE FALSE END AND se_classifieds.classified_classifiedcat_id=benjoe:$1$admin123$82WhhzvHQI7y1Taq83tiU1


Running sql injection am getting above error.. can any one help me to get correct syntx

don understand what am missing..

Thanks in advance..
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What it mean...
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