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Secure Enclave Key Theft, Wormable RCE, Crypto Theft Defense in depth -- the Microsoft way (part 89): user grouppolicies don't deserve tamper protection CVE-2025-45542: Time-Based Blind SQL Injection in CloudClassroom PHP Project v1.0 ERPNext v15.53.1 Stored XSS in bio Field Allows Arbitrary Script Execution in Profile Page ERPNext v15.53.1 Stored XSS in user_image Field Allows Script Execution via Injected Image Path Local information disclosure in apport and systemd-coredump Stored XSS via File Upload - adaptcmsv3.0.3 IDOR "Change Password" Functionality - adaptcmsv3.0.3 Stored XSS "Send Message" Functionality - adaptcmsv3.0.3 Authenticated File Upload to RCE - adaptcmsv3.0.3 Stored XSS in "Description" Functionality - cubecartv6.5.9 Multiple Vulnerabilities in SAP GuiXT Scripting CVE-2024-47081: Netrc credential leak in PSF requests library Exploit CVE-2019-9978: Remote Code Execution in Social Warfare WordPress Plugin (<= 3.5.2) IT Security and Insecurity Portal www.waraxe.us Forum Index -> Sql injection -> Basic SQL Injection View previous topic :: View next topic Basic SQL Injection Posted: Wed Feb 25, 2009 11:08 pm Cool_Man Beginner Joined: Feb 26, 2009 Posts: 3 Hi I'm trying to learn SQL injection (spent 4-5 hours). I have setup a basic PHP+APACHE+MYSQL development area; with a user table and a basic front end using PHP. I'm trying to do the basic SQL injection, where I'm inserting Code: '' or '' = ''"; inside one of the inputs. The result I'm getting is Code: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\xampp\login.php on line 20 --- Incorrect Username or Password --- However, I dont quite get how this is a exploit... (i know it sounds stupid) Posted: Wed Feb 25, 2009 11:16 pm slsl Advanced user Joined: Oct 14, 2008 Posts: 66 try different things what it is saying with that error is that your syntax is wrong try: Code: ' OR 1=1--+ " OR 1=1--+ it has to do with how your statment in the code is set up if your code was Code: SELECT * FROM USERS WHERE password = ' . $pass .' ORDER BY DESC you would use something like ' OR 1=1 --+ SQL injection is a common security flaw in sites where the don't sanitize user input that goes into SQL queries. This allows users to manipulate that database and the returned input in many ways, that is why I would call it an exploit. i recommend you visit a tutorial like http://www.securiteam.com/securityreviews/5DP0N1P76E.html Posted: Thu Feb 26, 2009 12:10 am Cool_Man Beginner Joined: Feb 26, 2009 Posts: 3 slsl wrote: Code: ' OR 1=1--+ Now i got three senarios If i use the above for both input boxes, I login as normal If I use it on only one inpux box, I dont login in however get error message If i use normal invalid username and password, i dont login with no error message Posted: Thu Feb 26, 2009 1:06 am slsl Advanced user Joined: Oct 14, 2008 Posts: 66 that would be because how the SQL query is formed. say the query is Code: SELECT * FROM users WHERE username = ' . $user . ' AND password = ' . $pass . ' when you use ' OR 1=1 --+ you are saying Grab the user from users table where username is NULL or if 1=1 grab a user. since 1=1 is always true it will grab all users in the database. if you use invalid info it is saying grab the user with that username AND that password but since it does not exist it returns NULL. Also you should know that the -- is the comment symbol in SQL so it disregards anything after the "--" If you don't really know how SQL works and how to form statements use http://www.w3schools.com/sql/ I Would recommend that site for almost any web programming language Posted: Fri Feb 27, 2009 11:39 pm Cool_Man Beginner Joined: Feb 26, 2009 Posts: 3 Thanks for the help I have done few experiments on UNION ALL SELECT and blind injection (brute...) Don't want to sound stupid but, is it possible to INSERT and DELETE data from the URL? because I have not managed to do it. What I have tried Code: www.example.com/users.php?id=2'; DELETE FROM users WHERE 1 or username = '"; Thanks Posted: Sat Feb 28, 2009 2:27 am waraxe Site admin Joined: May 11, 2004 Posts: 2407 Location: Estonia, Tartu In case of Mysql/Php you can't use stacked sql queries (separated by ; ). So you can manipulate with UPDATE only if there is sql injection in UPDATE query and same for INSERT and DELETE. 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